feat: kubesphere 4.0 (#6115)

* feat: kubesphere 4.0

Signed-off-by: ci-bot <ci-bot@kubesphere.io>

* feat: kubesphere 4.0

Signed-off-by: ci-bot <ci-bot@kubesphere.io>

---------

Signed-off-by: ci-bot <ci-bot@kubesphere.io>
Co-authored-by: ks-ci-bot <ks-ci-bot@example.com>
Co-authored-by: joyceliu <joyceliu@yunify.com>
This commit is contained in:
KubeSphere CI Bot
2024-09-06 11:05:52 +08:00
committed by GitHub
parent b5015ec7b9
commit 447a51f08b
8557 changed files with 546695 additions and 1146174 deletions

49
vendor/gopkg.in/ini.v1/error.go generated vendored Normal file
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// Copyright 2016 Unknwon
//
// Licensed under the Apache License, Version 2.0 (the "License"): you may
// not use this file except in compliance with the License. You may obtain
// a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
// WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
// License for the specific language governing permissions and limitations
// under the License.
package ini
import (
"fmt"
)
// ErrDelimiterNotFound indicates the error type of no delimiter is found which there should be one.
type ErrDelimiterNotFound struct {
Line string
}
// IsErrDelimiterNotFound returns true if the given error is an instance of ErrDelimiterNotFound.
func IsErrDelimiterNotFound(err error) bool {
_, ok := err.(ErrDelimiterNotFound)
return ok
}
func (err ErrDelimiterNotFound) Error() string {
return fmt.Sprintf("key-value delimiter not found: %s", err.Line)
}
// ErrEmptyKeyName indicates the error type of no key name is found which there should be one.
type ErrEmptyKeyName struct {
Line string
}
// IsErrEmptyKeyName returns true if the given error is an instance of ErrEmptyKeyName.
func IsErrEmptyKeyName(err error) bool {
_, ok := err.(ErrEmptyKeyName)
return ok
}
func (err ErrEmptyKeyName) Error() string {
return fmt.Sprintf("empty key name: %s", err.Line)
}